Profit and Loss
Important Formula:
1. Profit = SP-CP
2. Loss = CP-SP
3. Profit% = (Profit/ CP)*100
4.Loss % = ( Loss/CP)*100
5. For Dishonest shopkeeper :
% profit or % loss = (Error *100) / True Value
6. SP= MARKED PRICE - DISCOUNT
[ Whenever discount is given , it is given on Marked Price, hence in such case Marked Price should be treated as 100%]
6. SP= MARKED PRICE - DISCOUNT
[ Whenever discount is given , it is given on Marked Price, hence in such case Marked Price should be treated as 100%]
Important Points :
1.Always consider CP as 100% and then solve the question. Try to use all the variables in percentage form only.
2. CP should be the base value for calculating Profit or Loss .
2. CP should be the base value for calculating Profit or Loss .
3. For Successive Discount:
Net Discount = a+ b -(ab/100)
4. When CP1 = CP2 and profit% 1st = Loss% on 2nd,
then : NO PROFIT & NO LOSS in overall transaction.
5. When SP1 = SP2 and profit% 1st = Loss% on 2nd,
then : LOSS in overall transaction.
Loss% = (rate*rate)/100
4. When CP1 = CP2 and profit% 1st = Loss% on 2nd,
then : NO PROFIT & NO LOSS in overall transaction.
5. When SP1 = SP2 and profit% 1st = Loss% on 2nd,
then : LOSS in overall transaction.
Loss% = (rate*rate)/100
Solved Examples
Q1. A man sold a book at 480 Rs and he gained 20%. Find CP ?
Solution:
CP = 100% and SP= 120%
Here,
120% = 480
100% = x (i.e. CP)
Use cross multiplication and solve further,
x = 400
Q2.
If Mark Price of a TV set is 20% more than its CP. Shopkeeper gives discount of 5%. Find profit% ?
Solution:
CP = 100%
MP= 120%
SP = 120% - ( 5% of 120%) = 120% - 6% = 114%
Profit% = 114% - 100% = 14%.
Q3.
If CP is 96 % of SP. Find Profit %?
Solution:
Given that, CP= 96% and SP = 100%
profit = SP-CP = 100% - 96% = 4%
Profit% = (Profit/ CP)*100 = (4%/ 96%)*100 = 400/96 = 4.16 .
Q4. A Boy bought a bag with 15% discount on labelled price. He sold the bag for Rs 2880 with 20% profit on labelled price. At which price did he bought the bag?
Solution:
CP of bag = 100% of labelled price - 15% = 85% of labelled price is CP
120 % of labelled Price = 2880
85% of labelled price = x ( i.e. CP)
Use cross multiplication and solve further,
x = (2880*85%)/ 120% = Rs 2040.
Q5. A customer gets 2 discount of 40% and 20% . This discount is equivalent to how much discount?
solution:
Net Discount = a+ b -(ab/100)
Net discount = 40+20 - (40*20/100) = 60-8 = 52%.
alternate method:
100 - (40% of 100) - ( 20% of 40% of 100)
100-40-8 = 52%
Q6. A shopkeeper give 2 successive discount of 20% and 15 % on purchase of an article. Ia a boy pays Rs 1156 for that article then find the Marked price ?
solution
Net Discount = a+ b -(ab/100)
= 20+15- (20*15/ 100) = 35-3 = 32%
It means the Boy has paid 68 % [ as he get 32% discount]
now,
68% = 1156
100% = x ( i.e. marked price)
x = 1156*100 / 68 = Rs 1700.
Q7. A shopkeeper sell his good at CP., but he uses a weight of 960 gram instead of 1kg . Find his profit % ?
solution:
% profit = (Error *100) / True Value
=(40 *100)/960 = 4000/960 = 4.16.
Q8. A man purchases some lemon at 6 lemon per 5 Rs. and sell all the lemon at 4 lemon per 3 Rs.
Find Profit or loss % ?
solution:
Quantity Price
CP 6 5
SP 4 3
Please note , the TRICK is cross multiplication we will use SP as 6*3 [ from left top to right bottom] and CP as 4*5 [ from left bottom to right top ]
SP = 18
CP = 20
loss = 2
loss % = 2*100/20 = 2% loss.
Q9. A person bought two articles for the same price and sold them at a profit of 10% on one and a loss of 10% on the other. What is the overall profit or loss % made by him?
here,
CP1= CP2
PROFIT% = LOSS % = 10%
When CP1 = CP2 and profit% on 1st = Loss% on 2nd,
then : NO PROFIT &NO LOSS in overall transaction.
Q10.If a person sold two articles at same price and realized 10% profit on one and 10% loss on the other article. What net profit/loss % does he make?
here,
SP1= SP2
PROFIT% = LOSS % = 10%
LOSS in overall transaction.
Loss% = (rate*rate)/100 = (10*10)/100 = 1%.
Q11.A shopkeeper marks his goods in such a way that after allowing a discount of 10%, he gains 17%. How much percent above C.P. is the marked price?
Solve it using ,
Net percentage change = a+ b -(ab/100)
profit% = % change in MP (a)+ discount% (b)- ab/100
17 = a-10-(10a/100)
1700 = 100a-1000-10a
1700+1000 = 100a-10a
2700= 90a
a= 30
Marked price is 30% more than CP.
Q9. A person bought two articles for the same price and sold them at a profit of 10% on one and a loss of 10% on the other. What is the overall profit or loss % made by him?
here,
CP1= CP2
PROFIT% = LOSS % = 10%
When CP1 = CP2 and profit% on 1st = Loss% on 2nd,
then : NO PROFIT &NO LOSS in overall transaction.
Q10.If a person sold two articles at same price and realized 10% profit on one and 10% loss on the other article. What net profit/loss % does he make?
here,
SP1= SP2
PROFIT% = LOSS % = 10%
LOSS in overall transaction.
Loss% = (rate*rate)/100 = (10*10)/100 = 1%.
Q11.A shopkeeper marks his goods in such a way that after allowing a discount of 10%, he gains 17%. How much percent above C.P. is the marked price?
Solve it using ,
Net percentage change = a+ b -(ab/100)
profit% = % change in MP (a)+ discount% (b)- ab/100
17 = a-10-(10a/100)
1700 = 100a-1000-10a
1700+1000 = 100a-10a
2700= 90a
a= 30
Marked price is 30% more than CP.
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